#import "@youwen/zen:0.1.0": * #import "@preview/ctheorems:1.1.3": * #show: zen.with( title: "Homework 1", author: "Youwen Wu", date: "Winter 2025", ) #set enum(spacing: 2em) + #[ #set enum(numbering: "a)", spacing: 2em) + #[ We know that $B$ and $B'$ are disjoint. That is, $B sect B' = emptyset$. Additionally, $ E = (A sect B) subset B \ F = (A sect B') subset B' \ $ Then we note $ forall x in E, x in B, x in.not B' \ forall y in F, y in B, y in.not B' $ So clearly $E$ and $F$ have no common elements, and $ E sect F = emptyset $ ] + #[ $ E union F &= (A sect B) union (A sect B') \ &= (A union A) sect (B union B') \ &= A sect Omega \ &= A $ ] ] + #[ #set enum(numbering: "a)", spacing: 2em) + ${15, 25, 35, 45, 51, 53, 55, 57, 59, 65, 75, 85, 95 }$ + ${50, 52, 56, 58}$ + $emptyset$ ] + #[ #set enum(numbering: "a)", spacing: 2em) + The sample space is every value of the die (1-6) paired with heads and paired with tails. That is, ${1,2,3,4,5,6} times {H,T}$, with cardinality 12. + There are $12^10$ outcomes. + If no participants roll a 5, then we omit any outcome in our sample space where the die outcome is 5, leaving us with 10 outcomes of the die and coin. Now we have $10^10$ outcomes. If at least 1 person rolls a 5, then we note that this is simply the complement of the previous result. So we have $12^10 - 10^10$ outcomes total. ] + #[ #set enum(numbering: "a)", spacing: 2em) + #[ The sample space can be represented as a 6-tuple where the position 1-6 represents balls numbered 1-6, and the value represents the square it was sent to. So it's $ {{x_1,x_2,x_3,x_4,x_5,x_6} : x_i in {1,2,3,4}}, i = 1,...6 $ ] + #[ When the balls are indistinguishable, we can instead represent it as 4-tuples where the position represents the 1st, 2nd, 3rd, or 4th square, and the value represents how many balls landed. Additionally the sum of all the elements must be 6. $ {{x_1, x_2, x_3, x_4} : x_i >= 0, i = 1,...,6 sum_(j=1)^4 x_j = 6} $ ] ]