auto-update(nvim): 2025-01-06 18:28:44

This commit is contained in:
Youwen Wu 2025-01-06 18:28:44 -08:00
parent 560e8fdcb9
commit c1ad1cdec0
Signed by: youwen5
GPG key ID: 865658ED1FE61EC3
3 changed files with 61 additions and 21 deletions

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@ -1,5 +1,5 @@
#import "@preview/ctheorems:1.1.2": * #import "@preview/ctheorems:1.1.3": *
#import "@preview/showybox:2.0.1": showybox #import "@preview/showybox:2.0.3": showybox
#let colors = ( #let colors = (
rgb("#9E9E9E"), rgb("#9E9E9E"),
@ -257,27 +257,33 @@
shadow: (offset: (x: 2pt, y: 2pt), color: luma(70%)), shadow: (offset: (x: 2pt, y: 2pt), color: luma(70%)),
) )
#let problem = problem-style("problem", "Problem") #let exercise = problem-style("item", "Exercise")
#let problem = exercise
#let theorem-style = builder-thmbox( #let theorem-style = builder-thmbox(
color: colors.at(6), color: colors.at(6),
shadow: (offset: (x: 3pt, y: 3pt), color: luma(70%)), shadow: (offset: (x: 3pt, y: 3pt), color: luma(70%)),
) )
#let theorem = theorem-style("theorem", "Theorem") #let example-style = builder-thmbox(
#let lemma = theorem-style("lemma", "Lemma") color: colors.at(16),
#let corollary = theorem-style("corollary", "Corollary") shadow: (offset: (x: 3pt, y: 3pt), color: luma(70%)),
)
#let theorem = theorem-style("item", "Theorem")
#let lemma = theorem-style("item", "Lemma")
#let corollary = theorem-style("item", "Corollary")
#let definition-style = builder-thmline(color: colors.at(8)) #let definition-style = builder-thmline(color: colors.at(8))
#let definition = definition-style("definition", "Definition") // #let definition = definition-style("definition", "Definition")
#let proposition = definition-style("proposition", "Proposition") #let proposition = definition-style("item", "Proposition")
#let remark = definition-style("remark", "Remark") #let remark = definition-style("item", "Remark")
#let observation = definition-style("observation", "Observation") #let observation = definition-style("item", "Observation")
#let example-style = builder-thmline(color: colors.at(16)) // #let example-style = builder-thmline(color: colors.at(16))
#let example = example-style("example", "Example").with(numbering: none) #let example = example-style("item", "Example").with(numbering: none)
#let proof(body, name: none) = { #let proof(body, name: none) = {
thmtitle[Proof] thmtitle[Proof]
@ -289,3 +295,26 @@
h(1fr) h(1fr)
$square$ $square$
} }
#let fact = thmplain(
"item",
"Fact",
titlefmt: strong,
separator: ".",
inset: 0pt,
)
#let abuse = thmplain(
"item",
"Abuse of Notation",
titlefmt: strong,
separator: ".",
inset: 0pt,
)
#let definition = thmplain(
"item",
"Definition",
titlefmt: strong,
separator: ".",
inset: 0pt,
)

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@ -62,7 +62,8 @@ Definitions barely worth considering. Included purely for posterity.
$x^2 + 6x + 8 = 0$ $x^2 + 6x + 8 = 0$
] ]
Propositions may be stated in the formalism of mathematics using connectives, as *propositional forms*. Propositions may be stated in the formalism of mathematics using connectives,
as *propositional forms*.
#definition("Propositional forms")[ #definition("Propositional forms")[
Let $P$ and $Q$ be propositions. Then: Let $P$ and $Q$ be propositions. Then:

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@ -21,8 +21,14 @@
== Set theory for dummies == Set theory for dummies
A terse introduction to elementary set theory and the basic operations upon A terse introduction to elementary naive set theory and the basic operations
them. upon them.
#remark[
Keep in mind that without $cal(Z F C)$ or another model of set theory that
resolves fundamental issues, our set theory is subject to paradoxes like
Russell's.
]
#definition[ #definition[
A Set is a collection of elements. A Set is a collection of elements.
@ -51,7 +57,7 @@ With arbitrary sets $A$, $B$:
+ $a in.not A$ ($a$ is not a member of the set $A$) + $a in.not A$ ($a$ is not a member of the set $A$)
+ $A subset.eq B$ (Set theory: $A$ is a subset of $B$) (Stats: $A$ is a sample space in $B$) + $A subset.eq B$ (Set theory: $A$ is a subset of $B$) (Stats: $A$ is a sample space in $B$)
+ $A subset B$ (Proper subset: $A != B$) + $A subset B$ (Proper subset: $A != B$)
+ $A^c$ or $A'$ (read "complement of $A$") + $A^c$ or $A'$ (read "complement of $A$", and gives all the elements in the universal set not in $A$)
+ $A union B$ (Union of $A$ and $B$. Gives a set with both the elements of $A$ and $B$) + $A union B$ (Union of $A$ and $B$. Gives a set with both the elements of $A$ and $B$)
+ $A sect B$ (Intersection of $A$ and $B$. Gives a set consisting of the elements in *both* $A$ and $B$) + $A sect B$ (Intersection of $A$ and $B$. Gives a set consisting of the elements in *both* $A$ and $B$)
+ $A \\ B$ (Set difference. The set of all elements of $A$ that are not also in $B$) + $A \\ B$ (Set difference. The set of all elements of $A$ that are not also in $B$)
@ -64,12 +70,19 @@ We can also write a few of these operations precisely as set comprehensions.
+ $A sect B = {x | x in A and x in B}$ (here $and$ is the logical AND) + $A sect B = {x | x in A and x in B}$ (here $and$ is the logical AND)
+ $A \\ B = {a | a in A and a in.not B}$ + $A \\ B = {a | a in A and a in.not B}$
+ $A times B = {(a,b) | forall a in A, forall b in B}$ + $A times B = {(a,b) | forall a in A, forall b in B}$
+ $A' = A sect Omega$, where $Omega$ is the _universal set_.
#definition[
The universal set $Omega$ is the set of all objects in a given set
theoretical universe.
]
Take a moment and convince yourself that these definitions are equivalent to Take a moment and convince yourself that these definitions are equivalent to
the previous ones. the previous ones.
#example[The real plane][ #example[The real plane][
The real plane $RR^2$ can be defined as a Cartesian product of $RR$ with itself. The real plane $RR^2$ can be defined as a Cartesian product of $RR$ with
itself.
$ RR^2 = RR times RR $ $ RR^2 = RR times RR $
] ]
@ -118,10 +131,7 @@ When a set is uncountably infinite, its cardinality is greater than $aleph_0$.
+ The real numbers in the interval $[0,1]$. + The real numbers in the interval $[0,1]$.
] ]
#remark[Bijection][ #fact[
If a set is countably infinite, then it has a bijection with $ZZ$. This means If a set is countably infinite, then it has a bijection with $ZZ$. This means
every set with cardinality $aleph_0$ has a bijection to $ZZ$. every set with cardinality $aleph_0$ has a bijection to $ZZ$.
] ]